45x+9x^2=0

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Solution for 45x+9x^2=0 equation: 



45x+9x^2=0

a = 9; b = 45; c = 0;
Δ = b2-4ac
Δ = 452-4·9·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-45}{2*9}=\frac{-90}{18}
=-5
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+45}{2*9}=\frac{0}{18}
=0
$

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